# Pipes And Cisterns Aptitude Question and Answer

## Best explanation to understand and solve the problems on trains

This section is about the aptitude test based on PIPES AND CISTERNS. This is almost related to the concept of time and work, but with a slight difference in the terms where we use inlet and outlet here.

This article will definitely help you to clearly understand the topic and also to know about easy ways to solve pipes and cisterns aptitude problems.

Moreover, we have a collection of aptitude questions based on pipes and cisterns which you may use it to practice for your exams. Learn more about the topic and take up your exams confidently.

### What is called a pipe and cistern?

Pipe is nothing but a tube that is used to convey water, gas, oil or other liquid substances.

Cisterns are nothing but the tank that stores water or other liquid substances.

A pipe is always connected to a tank or cistern. It is used to fill a tank or empty a tank. Accordingly it is called an inlet or an outlet.

**What is inlet?**

A pipe which is connected to a tank and is used to fill a tank with water is known as an inlet.

**What is outlet?**

A pipe which is connected to a tank and is used to empty a tank that contains water is known as an outlet.

### What is the concept of pipes and cisterns?

Problems on pipes and cisterns are very similar to the problems on time and work.

In pipes and cistern aptitude, the amount of work done is nothing but the part of tank of filled or emptied with water or liquid. And, the time taken to do the work is the time taken to fill or empty a tank completely or to a given level.

### How to solve pipes and cisterns aptitude problems?

Here are some important methods to solve pipes and cisterns problems easily.

1. An inlet is connected to a tank and it fills the tank in X hours. So the part of the tank filled in one hour can be given by 1/X

2. An outlet is connected to a tank and it empties the tank in Y hours. So the part of the tank emptied in one hour can be given by 1/Y

3. An inlet can fill a tank in X hours and an outlet can empty the same tank in Y hours. If both the pipes are opened at the same time and Y > X, the net part of the tank filled in one hour can be given by

( 1 / X ) - ( 1 / Y )

Therefore, when both the pipes are open the time taken to fill the whole tank can be given by

= xy / ( y - x )

If X is greater than Y, more water is flowing out of the tank than flowing into the tank. And, the net part of the tank emptied in one hour can be given by

( 1 / Y ) - ( 1 / X )

Therefore, when both the pipes are open the time taken to empty the full tank can be given by

= xy / ( x - Y )

4. An inlet can fill a tank in X hours and another inlet can fill the same tank in Y hours. If both the inlets are opened at the same time, then the net part of the tank filled in one hour can be given by

( 1 / X ) + ( 1 / Y )

Therefore, the time taken to fill the whole tank can be given by

= xy / ( y + x )

At the same time, If an outlet can empty a tank in X hours and another outlet can empty the same tank in Y hours, the part of the tank emptied in one hour when both the pipes start working together can be given by

( 1 / X ) + ( 1 / Y )

Therefore, the time taken to empty the full tank is given by

= xy / ( y + x )

5. Three inlets A, B, and C can fill a tank in X, Y and Z hours respectively. If all the inlets are opened together,then the time taken to fill the tank can be given by

= ( x + y + z ) / ( xy + yz + zx )

6. Two pipes can fill a tank in X and Y hours respectively and an outlet can empty the same tank in Z hours. If all the pipes are opened together, the part of the tank filled in one hour can be given by

(1/X + 1/Y - 1/Z)

Therefore time taken to fill the tank completely when all the pipes are working can be given by

= xyz / xy + yz + xz

7. A pipe can fill a tank in X hours but due to a small leak in the bottom, it can be filled only in Y hours. The time taken by the leak to empty the tank can be given by

= xy / y - x

8. An inlet A is X times faster than inlet B and takes Y minutes less than the inlet B. time taken to fill the tank when both the pipes are opened together can be given by

= xy / (x - y)2

And, A alone will fill the tank in ( y / x-1) minitues

And, B alone will fill the tank in ( xy / x-1 )minitues

By the help of two faucet F1 and F2 a vessel can fill in 20 hours and 30 hours respectively. When the two faucet F1 and F2 start at same time then calculate the time taken to fill the vessel .

A drum get full by a liquid flowing from a faucet in 16 hours and the same drum empty by another faucet in 32 hours . If the incoming fluid faucet and outgoing fluid faucet open at a same time then calculate the time taken to fill the drum.

A man is pouring kerosene in a bottle of height 2.31 m and rectangular base of size 3 m * 5 m through a tube whose inner diameter is 7 cm at 5 m/sec. Calculate the time to full the bottle ?

In a Chemistry laboratory Tube 1 can full a vessel in 24 min and Tube 2 can full a vessel in 30 min . Then Rihan together start the two tube but after 6 min she close the Tube 1. calculate after how much further time will the vessel be filled ?

By spigot F1 it take 10 hrs and by spigot F2 it take 12 hrs to full a pail and by spigot F3 it take 20 hrs to empty the full pail which is fixed at the bottom the pail. If all the spigot work at the same time calculate the time to full the pail.

2 conduit U and W together can fill a vessel in 16 hours. If the conduit U and W opened separately then conduit W will take 24 hours more than conduit U. Calculate the time to fill the vessel by conduit U separately.

When 2 hose namely Black color hose and Green color hose function simultaneously the drum in the garden will be filled in 12 hours. Green color hose fills the drum in 10 hrs faster than the Black color hose. Calculate how many hours does it take the green color hose to fill the drum.

Out of 3 hose namely M, N and O , in 10 min and 15 min hose M and N occupy the capacity of a Beaker with liquid and in 20 min hose O vacant the Beaker.If the three hose start at same time calculate at what time the liquid will occupy the capacity of the Beaker?

The maximum volume of a Sintex is 2400 m³. The draining capability of Sintex is 10m³ per minute higher than its filling capability and the Piston pump needs 8 minutes less time to empty the Sintex than it needs to fill it. What is the filing capability of the Piston pump ?

Spout A can be full a flask in 20 minutes and Spout B can be full the same flask in 30 minutes . If we open the 2 spout at same time then calculate the time which the two spout will take to fill the flask.

G and H tube together cram an empty barrel in 10 minute. But G tube alone cram the empty barrel in 15 minute, then calculate the time at which H tube will take to cram the empty barrel.

From 2 valves U and V the keg can be fill to the brim , by U valve it take 4 minute and by V valve it take 12 minute. Measure the time to fill to the brim of the keg when we start both valve U and V.

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